Page 1286 - MISUMI SINGAPORE Economy Series

Economy series Technical Data - Mechanical Calculation
Aluminum Frames

ICalculation of Deformation Under Stress of Economy Series Industrial Aluminum Frames
Aluminum Frames When selecting economy series industrial aluminum frames, the deformation is an important basis for selection. The deformation of Frames Aluminum
aluminum frames under dead load and stress can be easily calculated using the following formula.

P.1183 m Linear density of aluminum frame (kg/mm ) I Collective inertia (cm ) P.1183
3
4
Brackets / Corners / Sheet Metals / Connectors F L E Load (N) 2 Z Cross section inertia (cm ) Sheet Metals / Connectors Brackets / Corners /
3
Length of aluminum frame without support (mm)
g=9.81N/kg
δ
Deformation (mm)
Longitudinal Elastic Modulus (70000N/mm )
P.1215 P.1215
1 One End Fixed 2 Support at Both Ends 3 Both Ends Fixed
Nuts / Bolts L/2 L/2 Nuts / Bolts
P.1243 F F F P.1243
Decorative Accessories L δ L δ L δ Accessories Decorative

P.1258 P.1258
Panel Fasteners / Panels / Door Sliding Slot Accessories I Calculation of deformation of aluminum frame under static load: Door Sliding Slot Accessories Panel Fasteners / Panels /

P.1262 δ1= F×L 3 δ2= F×L 3 δ3= F×L 3 P.1262
17 3E×I×10 4 48E×I×10 4 192E×I×10 4 17
Aluminum Frames / Related Accessories I Calculation of deformation of aluminum frame under no load: δ3= 384E×I×10 4 Related Accessories Aluminum Frames /

m×g×L
5×m×gL
m×g×L
4
4
4
δ1=
δ2=
8E×I×10
384E×I×10
4
4
I Maximum allowable bending stress of aluminum frame: Qmax<200N/m 2
(m×g×L+F)×L (m×g×L+F)×L (m×g×L+F)×L
Q1= Q2= Q3=
Z×10 3 4Z×10 3 8Z×10 3
I Example of calculation:
When SD-10-4545 aluminum frame is selected, length L=500mm, load F=800N (1kgf=9.81N), with fixed supports at both ends

800×500 3
Deformation δ= ≈ 0.05mm
192×70000×15.12×10 4

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